arm: Update mem* functions to newer versions
The memcpy/memset/memmove assembly implementations have been taken from U-Boot, which originally got them from Linux. I turns out that they are actually not that bad, but they could use an update. This patch pulls in the current Linux upstream versions of those files, removing some old U-Boot cruft such as checking whether the two pointers in a memcpy() are equal (really now?) or side-stepping the R8 register because it was used for special purposes. It also returns to the good old Linux ENTRY/ENDPROC macros since we have them now anyway, and straightens out the W() macro in preparation for unified thumb support. Change-Id: I138af269b423bef0a237759ac29f1ee58ca206a0 Signed-off-by: Julius Werner <jwerner@chromium.org> Reviewed-on: https://chromium-review.googlesource.com/182179 Reviewed-by: Vincent Palatin <vpalatin@chromium.org> (cherry picked from commit 777127997bde5785b21d422d0b6eb04c4328b478) Signed-off-by: Isaac Christensen <isaac.christensen@se-eng.com> Reviewed-on: http://review.coreboot.org/6918 Tested-by: build bot (Jenkins) Reviewed-by: David Hendricks <dhendrix@chromium.org>
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Isaac Christensen
parent
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commit
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@ -9,33 +9,21 @@
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*
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* ASM optimised string functions
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*/
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#include "assembler.h"
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#include <arch/asm.h>
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#include "asmlib.h"
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.text
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.align 5
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.word 0
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1: subs r2, r2, #4 @ 1 do we have enough
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blt 5f @ 1 bytes to align with?
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cmp r3, #2 @ 1
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strltb r1, [r0], #1 @ 1
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strleb r1, [r0], #1 @ 1
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strb r1, [r0], #1 @ 1
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add r2, r2, r3 @ 1 (r2 = r2 - (4 - r3))
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/*
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* The pointer is now aligned and the length is adjusted. Try doing the
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* memset again.
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*/
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.type memset, function
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.globl memset
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memset:
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ENTRY(memset)
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ands r3, r0, #3 @ 1 unaligned?
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bne 1b @ 1
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mov ip, r0 @ preserve r0 as return value
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bne 6f @ 1
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/*
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* we know that the pointer in r0 is aligned to a word boundary.
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* we know that the pointer in ip is aligned to a word boundary.
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*/
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orr r1, r1, r1, lsl #8
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1: orr r1, r1, r1, lsl #8
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orr r1, r1, r1, lsl #16
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mov r3, r1
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cmp r2, #16
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@ -44,29 +32,28 @@ memset:
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#if ! CALGN(1)+0
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/*
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* We need an extra register for this loop - save the return address and
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* use the LR
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* We need 2 extra registers for this loop - use r8 and the LR
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*/
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str lr, [sp, #-4]!
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mov ip, r1
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stmfd sp!, {r8, lr}
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mov r8, r1
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mov lr, r1
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2: subs r2, r2, #64
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stmgeia r0!, {r1, r3, ip, lr} @ 64 bytes at a time.
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stmgeia r0!, {r1, r3, ip, lr}
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stmgeia r0!, {r1, r3, ip, lr}
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stmgeia r0!, {r1, r3, ip, lr}
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stmgeia ip!, {r1, r3, r8, lr} @ 64 bytes at a time.
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stmgeia ip!, {r1, r3, r8, lr}
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stmgeia ip!, {r1, r3, r8, lr}
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stmgeia ip!, {r1, r3, r8, lr}
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bgt 2b
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ldmeqfd sp!, {pc} @ Now <64 bytes to go.
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ldmeqfd sp!, {r8, pc} @ Now <64 bytes to go.
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/*
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* No need to correct the count; we're only testing bits from now on
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*/
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tst r2, #32
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stmneia r0!, {r1, r3, ip, lr}
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stmneia r0!, {r1, r3, ip, lr}
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stmneia ip!, {r1, r3, r8, lr}
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stmneia ip!, {r1, r3, r8, lr}
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tst r2, #16
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stmneia r0!, {r1, r3, ip, lr}
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ldr lr, [sp], #4
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stmneia ip!, {r1, r3, r8, lr}
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ldmfd sp!, {r8, lr}
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#else
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@ -75,53 +62,63 @@ memset:
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* whole cache lines at once.
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*/
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stmfd sp!, {r4-r7, lr}
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stmfd sp!, {r4-r8, lr}
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mov r4, r1
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mov r5, r1
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mov r6, r1
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mov r7, r1
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mov ip, r1
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mov r8, r1
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mov lr, r1
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cmp r2, #96
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tstgt r0, #31
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tstgt ip, #31
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ble 3f
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and ip, r0, #31
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rsb ip, ip, #32
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sub r2, r2, ip
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movs ip, ip, lsl #(32 - 4)
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stmcsia r0!, {r4, r5, r6, r7}
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stmmiia r0!, {r4, r5}
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tst ip, #(1 << 30)
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mov ip, r1
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strne r1, [r0], #4
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and r8, ip, #31
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rsb r8, r8, #32
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sub r2, r2, r8
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movs r8, r8, lsl #(32 - 4)
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stmcsia ip!, {r4, r5, r6, r7}
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stmmiia ip!, {r4, r5}
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tst r8, #(1 << 30)
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mov r8, r1
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strne r1, [ip], #4
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3: subs r2, r2, #64
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stmgeia r0!, {r1, r3-r7, ip, lr}
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stmgeia r0!, {r1, r3-r7, ip, lr}
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stmgeia ip!, {r1, r3-r8, lr}
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stmgeia ip!, {r1, r3-r8, lr}
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bgt 3b
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ldmeqfd sp!, {r4-r7, pc}
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ldmeqfd sp!, {r4-r8, pc}
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tst r2, #32
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stmneia r0!, {r1, r3-r7, ip, lr}
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stmneia ip!, {r1, r3-r8, lr}
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tst r2, #16
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stmneia r0!, {r4-r7}
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ldmfd sp!, {r4-r7, lr}
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stmneia ip!, {r4-r7}
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ldmfd sp!, {r4-r8, lr}
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#endif
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4: tst r2, #8
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stmneia r0!, {r1, r3}
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stmneia ip!, {r1, r3}
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tst r2, #4
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strne r1, [r0], #4
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strne r1, [ip], #4
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/*
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* When we get here, we've got less than 4 bytes to zero. We
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* may have an unaligned pointer as well.
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*/
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5: tst r2, #2
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strneb r1, [r0], #1
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strneb r1, [r0], #1
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strneb r1, [ip], #1
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strneb r1, [ip], #1
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tst r2, #1
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strneb r1, [r0], #1
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strneb r1, [ip], #1
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mov pc, lr
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6: subs r2, r2, #4 @ 1 do we have enough
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blt 5b @ 1 bytes to align with?
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cmp r3, #2 @ 1
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strltb r1, [ip], #1 @ 1
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strleb r1, [ip], #1 @ 1
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strb r1, [ip], #1 @ 1
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add r2, r2, r3 @ 1 (r2 = r2 - (4 - r3))
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b 1b
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ENDPROC(memset)
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