aa1b377e71
Change license to BSD-2-Clause-Patent using an SPDX-License-Identifier statement. Cc: Liming Gao <liming.gao@intel.com> Cc: Leif Lindholm <leif@nuviainc.com> Cc: Ard Biesheuvel <ard.biesheuvel@arm.com> Signed-off-by: Michael D Kinney <michael.d.kinney@intel.com> Reviewed-by: Leif Lindholm <leif@nuviainc.com> Acked-by: Ard Biesheuvel <ard.biesheuvel@arm.com>
122 lines
4.1 KiB
NASM
122 lines
4.1 KiB
NASM
; Copyright (c) 2010-2011, Linaro Limited
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; All rights reserved.
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; SPDX-License-Identifier: BSD-2-Clause-Patent
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;
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;
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; Written by Dave Gilbert <david.gilbert@linaro.org>
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;
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; This memchr routine is optimised on a Cortex-A9 and should work on
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; all ARMv7 processors. It has a fast past for short sizes, and has
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; an optimised path for large data sets; the worst case is finding the
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; match early in a large data set.
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;
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; 2011-02-07 david.gilbert@linaro.org
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; Extracted from local git a5b438d861
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; 2011-07-14 david.gilbert@linaro.org
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; Import endianness fix from local git ea786f1b
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; 2011-12-07 david.gilbert@linaro.org
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; Removed unneeded cbz from align loop
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; this lets us check a flag in a 00/ff byte easily in either endianness
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#define CHARTSTMASK(c) 1<<(c*8)
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EXPORT InternalMemScanMem8
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AREA ScanMem, CODE, READONLY
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THUMB
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InternalMemScanMem8
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; r0 = start of memory to scan
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; r1 = length
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; r2 = character to look for
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; returns r0 = pointer to character or NULL if not found
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uxtb r2, r2 ; Don't think we can trust the caller to actually pass a char
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cmp r1, #16 ; If it's short don't bother with anything clever
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blt L20
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tst r0, #7 ; If it's already aligned skip the next bit
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beq L10
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; Work up to an aligned point
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L5
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ldrb r3, [r0],#1
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subs r1, r1, #1
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cmp r3, r2
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beq L50 ; If it matches exit found
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tst r0, #7
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bne L5 ; If not aligned yet then do next byte
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L10
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; At this point, we are aligned, we know we have at least 8 bytes to work with
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push {r4-r7}
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orr r2, r2, r2, lsl #8 ; expand the match word across to all bytes
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orr r2, r2, r2, lsl #16
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bic r4, r1, #7 ; Number of double words to work with
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mvns r7, #0 ; all F's
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movs r3, #0
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L15
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ldmia r0!, {r5,r6}
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subs r4, r4, #8
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eor r5, r5, r2 ; Get it so that r5,r6 have 00's where the bytes match the target
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eor r6, r6, r2
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uadd8 r5, r5, r7 ; Parallel add 0xff - sets the GE bits for anything that wasn't 0
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sel r5, r3, r7 ; bytes are 00 for none-00 bytes, or ff for 00 bytes - NOTE INVERSION
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uadd8 r6, r6, r7 ; Parallel add 0xff - sets the GE bits for anything that wasn't 0
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sel r6, r5, r7 ; chained....bytes are 00 for none-00 bytes, or ff for 00 bytes - NOTE INVERSION
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cbnz r6, L60
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bne L15 ; (Flags from the subs above) If not run out of bytes then go around again
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pop {r4-r7}
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and r2, r2, #0xff ; Get r2 back to a single character from the expansion above
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and r1, r1, #7 ; Leave the count remaining as the number after the double words have been done
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L20
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cbz r1, L40 ; 0 length or hit the end already then not found
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L21 ; Post aligned section, or just a short call
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ldrb r3, [r0], #1
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subs r1, r1, #1
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eor r3, r3, r2 ; r3 = 0 if match - doesn't break flags from sub
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cbz r3, L50
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bne L21 ; on r1 flags
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L40
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movs r0, #0 ; not found
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bx lr
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L50
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subs r0, r0, #1 ; found
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bx lr
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L60 ; We're here because the fast path found a hit - now we have to track down exactly which word it was
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; r0 points to the start of the double word after the one that was tested
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; r5 has the 00/ff pattern for the first word, r6 has the chained value
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cmp r5, #0
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itte eq
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moveq r5, r6 ; the end is in the 2nd word
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subeq r0, r0, #3 ; Points to 2nd byte of 2nd word
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subne r0, r0, #7 ; or 2nd byte of 1st word
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; r0 currently points to the 3rd byte of the word containing the hit
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tst r5, #CHARTSTMASK(0) ; 1st character
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bne L61
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adds r0, r0, #1
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tst r5, #CHARTSTMASK(1) ; 2nd character
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ittt eq
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addeq r0, r0 ,#1
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tsteq r5, #(3 << 15) ; 2nd & 3rd character
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; If not the 3rd must be the last one
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addeq r0, r0, #1
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L61
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pop {r4-r7}
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subs r0, r0, #1
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bx lr
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END
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